P = 100 T . Tensión del terreno = 1 Kg/cm2 = 10 T/m2

a²=(P/ Tension terreno)=100 T/10 T/m²

Tensión del terreno = 100T/(3.15m)²= 10.078 T/m²

. 0.15 x b (ancho del pilar) = 0.15 x 0.4 = 0.06 m

. c = (3.15/2) - 0.2 + 0.06 = 1.435 m

H = ((3.15/2) - 0.2) x tg 30 = 0.793 m = 0.8 m

d = H - 5 cm = 0.75

R = 10 T/m2 x 3.15 m x 1.435 m = 45.55 T

M = 45.55 T x (1.435 m / 2) = 32.68 Tm

A (área redondos) = (1.6 x 32.68 Tm) / (0.85 x 0.75 m x (4.1 T/cm2 / 1.2)) = 24 cm2

12 redondos de diámetro 16 (el área de un redondo del 16 vale 2.02 cm)

t b = Vd1 / (0.9 x d x n x u ) < t bd

R = 45.55 x 1.6 = 72.88 T = Vd1

d = 0.75 m

u = 2p r = 2 x p x 0.008 = 0.0508 m

n = 12 redondos

t bd = 0.95 x (fcd) = 22.67 Kp/cm2 . fcd = 175 / 1.5 Kp/cm2 (resistencia característica mayorada del hormigón)

t b = 17.70 Kg/cm2 < 22.67 Kg/cm2

R =10 T/m² x(3.15²x 1.15²)m² = 86 T

Cortante = R x 1.6 / (4 x (0.4+d) x d) < 2 x fcv

fcv=0.5x(fcd)½ (resistencia caracteristica del hormigón)= 0.5x(175/1.5)½=10.80 kg/cm²

Cortante = 86 T x (1.6 / (4 x (0.4 + 0.75) x 0.75)) = 39.88 T/m2 = 3.988 Kg/cm2

3.99 Kg/cm2 < 10.80 Kg/cm2